b^2=36-5b

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Solution for b^2=36-5b equation:


Simplifying
b2 = 36 + -5b

Solving
b2 = 36 + -5b

Solving for variable 'b'.

Reorder the terms:
-36 + 5b + b2 = 36 + -5b + -36 + 5b

Reorder the terms:
-36 + 5b + b2 = 36 + -36 + -5b + 5b

Combine like terms: 36 + -36 = 0
-36 + 5b + b2 = 0 + -5b + 5b
-36 + 5b + b2 = -5b + 5b

Combine like terms: -5b + 5b = 0
-36 + 5b + b2 = 0

Factor a trinomial.
(-9 + -1b)(4 + -1b) = 0

Subproblem 1

Set the factor '(-9 + -1b)' equal to zero and attempt to solve: Simplifying -9 + -1b = 0 Solving -9 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -1b = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -1b = 0 + 9 -1b = 0 + 9 Combine like terms: 0 + 9 = 9 -1b = 9 Divide each side by '-1'. b = -9 Simplifying b = -9

Subproblem 2

Set the factor '(4 + -1b)' equal to zero and attempt to solve: Simplifying 4 + -1b = 0 Solving 4 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-4' to each side of the equation. 4 + -4 + -1b = 0 + -4 Combine like terms: 4 + -4 = 0 0 + -1b = 0 + -4 -1b = 0 + -4 Combine like terms: 0 + -4 = -4 -1b = -4 Divide each side by '-1'. b = 4 Simplifying b = 4

Solution

b = {-9, 4}

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